-.0625x^2+2.7x=3

Solution for -.0625x^2+2.7x=3 equation:

-.0625x^2+2.7x=3

We move all terms to the left:

-.0625x^2+2.7x-(3)=0

We add all the numbers together, and all the variables

-0.0625x^2+2.7x-3=0

a = -0.0625; b = 2.7; c = -3;
Δ = b2-4ac
Δ = 2.72-4·(-0.0625)·(-3)
Δ = 6.54
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.7)-\sqrt{6.54}}{2*-0.0625}=\frac{-2.7-\sqrt{6.54}}{-0.125}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.7)+\sqrt{6.54}}{2*-0.0625}=\frac{-2.7+\sqrt{6.54}}{-0.125}
$